QUESTION 1The following data was collected from a simple ran

QUESTION 1The following data was collected from a simple random sample of a population.1315141612The point estimate of the population meancannot be determined, since the population size is unknownis 14is 4is 54 points  QUESTION 2The following information was collected from a simple random sample of a population.161918172018The point estimate of the population standard deviation is2.0001.2911.4141.6674 points  QUESTION 3As a rule of thumb, the sampling distribution of the sample proportions can be approximated by a normal probability distribution whenevernp  5n(1 – p)  5 and n  30n  30 and (1 – p) = 0.5None of these alternatives is correct.4 points  QUESTION 4Random samples of size 36 are taken from an infinite population whose mean and standard deviation are 20 and 15, respectively. The distribution of the population is unknown. The mean and the standard error of the mean are36 and 1520 and 1520 and 0.41720 and 2.54 points  QUESTION 5A population has a mean of 180 and a standard deviation of 24. A sample of 64 observations will be taken. The probability that the sample mean will be between 183 and 186 is0.13590.81850.34130.47724 points  QUESTION 6A random sample of 150 people was taken from a very large population. Ninety of the people in the sample were female. The standard error of the proportion is0.00160.24000.16000.04004 points  QUESTION 7A sample of 66 observations will be taken from an infinite population. The population proportion equals 0.12. The probability that the sample proportion will be less than 0.1768 is0.05680.07780.42220.92224 points  QUESTION 8In general, higher confidence levels providewider confidence intervalsnarrower confidence intervalsa smaller standard errorunbiased estimates4 points  QUESTION 9Exhibit 8-3The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customers to check out was 3.0 minutes. It is known that the standard deviation of the population of checkout times is one minute.Refer to Exhibit 8-3. With a .95 probability, the sample mean will provide a margin of error of1.960.100.1961.644 points  QUESTION 10Exhibit 8-1In order to estimate the average time spent on the computer terminals per student at a local university, data were collected for a sample of 81 business students over a one-week period. Assume the population standard deviation is 1.8 hours.Refer to Exhibit 8-1. If the sample mean is 9 hours, then the 95% confidence interval is7.04 to 110.96 hours7.36 to 10.64 hours7.80 to 10.20 hours8.61 to 9.39 hours4 points  QUESTION 11Exhibit 8-2A random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph. From past information, it is known that the standard deviation of the population is 22 mph.Refer to Exhibit 8-2. The 96.6% confidence interval for m is63.00 to 67.0060.76 to 69.2461.08 to 68.9260.00 to 80.004 points  QUESTION 12The t value for a 95% confidence interval estimation with 24 degrees of freedom is1.7112.0642.4922.0694 points  QUESTION 13In a random sample of 144 observations,  = 0.6. The 95% confidence interval for P is0.52 to 0.680.144 to 0.2000.60 to 0.700.50 to 0.704 points  QUESTION 14The following random sample from a population whose values were normally distributed was collected.1081111The 95% confidence interval for m is8.52 to 10.987.75 to 11.759.75 to 10.758.00 to 10.004 points  QUESTION 15A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would be defective. With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is110111216217

"Our Prices Start at $11.99. As Our First Client, Use Coupon Code GET15 to claim 15% Discount This Month!!":

Get started
0 replies

Leave a Reply

Want to join the discussion?
Feel free to contribute!

Leave a Reply

Your email address will not be published.